If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x=x^2-2
We move all terms to the left:
5x-(x^2-2)=0
We get rid of parentheses
-x^2+5x+2=0
We add all the numbers together, and all the variables
-1x^2+5x+2=0
a = -1; b = 5; c = +2;
Δ = b2-4ac
Δ = 52-4·(-1)·2
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{33}}{2*-1}=\frac{-5-\sqrt{33}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{33}}{2*-1}=\frac{-5+\sqrt{33}}{-2} $
| Y=75/x | | 2(1-x)=14 | | 2x+7=2(3x-16) | | 7s+2*6=-2 | | 1.6y+y-4/15y+(1y+1/6y)=2+1/3 | | 3z/8+3=2 | | 1.6y+y-4/15+(1+1/6)=2+1/3 | | -5+4=16-2x | | x4+4x-126=0 | | 2y2=32 | | 5x=6=36 | | 4x-12=5x=10 | | 2(10x=3)-x=44 | | 10x-5=2x-3 | | 3x-12=5x=10 | | 3b+14=^18-5b | | (3k-2)(2k-1)=k(6k+5)-3 | | 6c^-3c=0 | | 1/3x^2-44=0 | | 11) 40+c=9+2c | | 3•(5-x)=15 | | 5x-(x-1)+2=2x+3+2x | | 0,5x+1=x-5 | | 3b+14=-18^5b | | 4x(2x-9)=-2(5x-6) | | 0x5x+1=x-5 | | 2(5x+10)=3(4x+6)+2 | | -6h+14=-8h-12 | | -2x+8+x+1=-x | | 144=3(48-1y)+3y | | 20(15m-10)=10(20+10m) | | 4b+7=-26-7b |